WILL GIVE BRAINLIEST! Find an equation of the circle and sketch it if it has: Tangent to y-axis, r=5, contains (10, 7)

Center = (5,7)

Radius = 5

Explanation:

The circle must be tangent to the y axis, and it has a radius of 5, so that means the center (h,k) must either be on the line x = 5 or x = -5, since those vertical lines are exactly five units away from the y axis.

But we're also told that (10,7) must be on the circle. That rules out x = -5 because the distance from (10,7) to (-5,k) is going to be larger than 5. I recommend drawing out a right triangle to see why this is the case.

So the center (h,k) must be on the line x = 5.

The center is the point (h,k) = (5,k)

Plug that h value along with (x,y) = (10,7) and r = 5 into the equation below

Solve for k.

(x-h)^2 + (y-k)^2 = r^2

(x-5)^2 + (y-k)^2 = 5^2 plug in h = 5 and r = 5

(10-5)^2 + (7-k)^2 = 25 ... plug in x = 10 and y = 7

25 + (7-k)^2 = 25

(7-k)^2 = 25-25

(7-k)^2 = 0

7-k = sqrt(0)

7-k = 0

-k = 0-7

-k = -7

k = 7

The center is (h,k) = (5,7)

We have (x-h)^2 + (y-k)^2 = r^2 updating to (x-5)^2 + (y-7)^2 = 25

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

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part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

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part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).

a

step-by-step explanation:

the answer is a