What is an equation of the line that passes through the points (-6,-3) and (-3,-5) ?

y = -2/3 x - 7

Step-by-step explanation:

Solve for the slope first:

m = (y2 - y1) / (x2 - x1)

= [(-5) - (-3)] / [(-3) - (-6)]

= (-5 + 3) / (-3 + 6)

= -2 / 3

Use any of the ordered pairs to find the value of b: (-6, -3)

y = mx + b

-3 = (-2/3)(-6) + b

-3 = 12/3 + b

-3 = 4 + b

-3 - 4 = b

-7 = b

To find the equation of the line substitute the b value and the slope.

y = mx + b

y = -2/3 x - 7

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

(a) the volume of the cone is 20/3 in3

hence, option a is correct.