What are the values of x, and y?

if this came out of a book use slader

Step-by-step explanation:

AnswersMathsGCSEArticle

What are the values of x and y?

a) 3x + 5y = 26

b) 2x + 2y = 12

Step One: We need to find a way to equate either the x terms of the y terms in each equation. Multiply equation a) by 2 and equation b) by 3 to form the following equations.

a) 6x + 10y = 52

b) 6x + 6y = 36

Step Two: Take equation b) from equation a) to eliminate the x component.

a) 6x + 10y = 52

- b) 6x + 6y = 36

0x + 4y = 16

y = 4

Step Three: substitute the value of y into either equation to find the value of x.

b) 2x + 2y = 12

2x + (2x4) =12

2x + 8 = 12

2x = 4

x = 2

x=2 y=4

Step-by-step explanation:

thank you sana nakatulong yang sagot ko

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.