What is the minimum angle of rotation (in degrees) that will carry the six-sided star onto itself?

The angle of rotation pf a six sided star, that will carry the six sided star onto itself is 60°

Step-by-step explanation:

The angle of rotation that will carry a six sided star onto itself is the angle between two adjacent lines of symmetry of the six sided star

Given that there are three lines of symmetry of the six sided star, and each line intersect with the next line at the center of the figure, the angle between two adjacent lines of symmetry = 360°/(2 × 3) = 60°

Therefore, the angle of rotation pf a six sided star, that will carry the six sided star onto itself = 60°.

answer: i believe its b. if you sound out the sentences that sounds wrong.

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb