Hellppp!
find the value of n when the nth term of sequence A is 576

The 6th term of sequence A is 25, since it's the next perfect square after 16.

The 6th term of sequence B is 9. This sequence is arithmetic with common difference 1, so we just add 1 to the last term to get the next one.

The 6th term of sequence C is 16. Simply subtract the values in the two boxes above (A-B = 25-9 = 16).

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Note that the general term for sequence A is (n-1)^2. Whatever n is, subtract 1, then square it. For example, if n = 6, then (n-1)^2 = (6-1)^2 = 25.

We're told that 576 is some term and we need to find what term number n.

So,

(n-1)^2 = 576

n-1 = sqrt(576) ... note that

n-1 = 24

n = 24+1

n = 25

So the 25th term is when 576 will show up.

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation: