There are only blue sweets green sweets and red

The greatest possible number of red sweets is 28

Step-by-step explanation:

Let the common ratio between blue and red sweets be x

Then,

Number of blue sweets = 2x

Number of green sweets = 7x

If the common ratio between the green and red sweets be y

Then,

Number of green sweets = 3y

Number of red sweets = y

Here the number of green sweets must be equal

Therefore,

Also the sum of all of them is 140

Thus,

x should be a whole number

Therefore,  

And the sum of all the sweets will be 136

Therefore,

Thus the greatest possible number of red sweets is 28

Hope this helps.

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75