Given: ∆DEK, DE = EK
EF −∠ bisector of ∠E
m∠DEF=44°, DK = 16
Find: KF, m∠DEK, m∠D...
Mathematics, 25.10.2020 20:20 skullcandy1396
Given: ∆DEK, DE = EK
EF −∠ bisector of ∠E
m∠DEF=44°, DK = 16
Find: KF, m∠DEK, m∠DFE
Answers: 2
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