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Mathematics, 25.10.2020 20:20 skullcandy1396

Given: ∆DEK, DE = EK EF −∠ bisector of ∠E
m∠DEF=44°, DK = 16

Find: KF, m∠DEK, m∠DFE


Given: ∆DEK, DE = EK

EF −∠ bisector of ∠E
m∠DEF=44°, DK = 16
Find: KF, m∠DEK, m∠DFE

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Answers: 2

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Given: ∆DEK, DE = EK EF −∠ bisector of ∠E
m∠DEF=44°, DK = 16

Find: KF, m∠DEK, m∠D...
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