What is the equation of the line that is parallel to the line defined by the equation y = 2x + 4 and goes through the point (3, 2)?

Step-by-step explanation:

Hey there!

Given;

y = 2x + 4(i)

The point is; (3,2). The equation of line which passes through this point is;

(y-y1) = m2(x-x1)

(y-2)= m2(x-3)(ii)

From equation (i).

y = 2x+4

Comparing the equation with y = mx+c, we get;

Slope (m1)= 2

As per the condition of parallel lines, (m1=m2).

Therefore, m2= 2.

Now, keeping the slope of m1 in eqaution (ii)

(y-2)= 2(x-3)

y - 2 = 2x - 6

y = 2x -4

Therefore, the equation is y = 2x - 4.

Hope it helps...

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.