Write an equation of the line passing through point p (2,3) that is perpendicular to the line y-4 = -2(x+3)

y - 3 = (x - 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 4 = - 2(x + 3) ← is in point- slope form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

= - = - =

passing through (2, 3 ), then

y - 3 = (x - 2) ← equation of perpendicular line

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.