A cloth bag contains 6 cards numbered 1 through 6. Two cards are drawn without replacement. What is the probability that the sum of the numbers on the two drawn cards is 7

Step-by-step explanation:

Given : A cloth bag contains 6 cards numbered 1 through 6. Two cards are drawn without replacement.

Favorable outcome: sum of the numbers on the two drawn cards is 7

Since 1+6 = 7 , 2+5=7, 4+3 = 7

So, sum of 7 can be obtained as (1, 6), (2, 5), (3, 4), (4, 3), (5, 2) and (6, 1)

Probability of getting (first 1, second 6) =

Probability of getting (first 2, second 5) = (

Probability of getting (first 3, second 4) =

Probability of getting (first 4, second 3) =

Probability of getting (first 5, second 2) =

Probability of getting (first 6, second 1) =

Required probability =

Hence, the required probability =

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option