Scores of 50 college students who have taken a statistics test has a mean of 82 and a standard deviation of 5. Construct a 99 % confidence interval for the mean score. Also, report the critical value LaTeX: z_cz c corresponding to a confidence level of c

(80.1786, 83.8214)

Step-by-step explanation:

Confidence interval for population mean is given by :-

, where = Sample mean , n= sample size , = standard deviation, = critical z-value.

Given: n= 50,   ,

Critical z-value for 99% confidence level = 2.576

Now, a 99 % confidence interval for the mean:

Hence, required 99% confidence interval = (80.1786, 83.8214)

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3