If we assume that snowfall during the month of March in Champaign-Urbana is normally distributed with a mean of 3.55 inches and a standard deviation of 3.65 inches, what is the probability that it snows 8 inches or more on in a given March in CU

The probability that it snows 8 inches or more in a given March is 0.11123

Step-by-step explanation:

To calculate this probability, we shall need to calculate the z-score first

Mathematically;

z-score = (x - mean)/SD

in this question, x = 8 inches

mean = 3.55 inches

SD = 3.65 inches

So the z-score will be;

(8-3.55)/3.65 = 1.22

So the probability we want to calculate is;

P ( z > 1.22)

we can calculate this using the standard normal distribution table

So P( z > 1.22) = 0.11123

whole number data type

step-by-step explanation:

as whole number type represents whole number

like 1, 2 ,3, 4

in other words the whole numbers are those numbers which cannot be written infraction.

since we can take days as a whole number i.e 1 day 2 day and we cannot write 1.2 day hence we will use whole number data type

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus