You car's check engine light comes on. You go to 2 different mechanics to find pricing. Mechanic A charges $125 to look over the car and $ 75 an hour to repair.
Mechanic B charges $100 to look over the car and $ 95 an hour to repair. If the
repairs take 3 hours, how much would each mechanic cost and which is a better
option?

Mechanic A

A: 350

B: 385

Step-by-step explanation:

We can create 2 equations based on the given info.

For mechanic a:

75x+125

(where x = number of hours)

For mechanic b:

95x+100

(x = number of hours)

We can create these equations because the initial cost of each is 125 and 100 respectively, and the cost per hour is 75 and 95 respectively.

Plug in the number of hours in each equation to get the cost.

answer: i cant see the graphs but i can you find the answer

step-by-step explanation:

the first point we'll be 0,0 and then you go up the y axis 4 places and over to the right 1 so your second point will be 1,4

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2