Please help me! Quick! Stephen Draws figure ABCD in the coordinate plane. He rotates figure ABCD 270 degrees clockwise around the vertex B to form image A'B'C'D'. What are the coordinates of figure A'B'C'D? Show your work.

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.

bdhfnfhjffjkfjfjfjjf

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)