Find the equation of a line parallel to 2x + 2y=6 that contains the point (3,-5), Write the equation in slope-intercept

Step-by-step explanation:

Slope-Intercept form of the line

Any given line with slope m and y-intercept b can be written as:

y=mx+b

We need to find the equation of a line parallel to

2x + 2y = 6

Dividing by 2:

x + y = 3

Solving for y:

y = -x + 3

Comparing with the slope-intercept form of the line:

m = -1

Parallel lines have the same slope, thus the required line must have a slope m = -1.

Since we have a point through which the line passes, we use the point-slope form:

y - k = m ( x - h )

Where (h,k) is the point.

The required equation of the line is:

y - (-5) = -1 (x - 3)

Operating:

y + 5 = -x + 3

Solving for y:

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb