PLEASE HELP ME OUT I ONLY HAVE 5 MIN TO TURN THIS IN
Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the given equation.
Equation:
(1, 1), 3x + 2y = –7

y = -3/2x + 2.5

Step-by-step explanation:

3​x ​+ 2​y ​= –7

2y = -3x - 7

y = -3/2x -7/2

y-intercept:

  y = mx + b

  1 = -3/2(1) + b

  1 = -3/2 + b

  b = 2.5

equation in slope-intercept form using above slope and b:

y = mx + b

y = -3/2x + 2.5

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .