A revolving light is located 0.5 miles from a straight shoreline. If the beam of light is moving at 2 miles per minute along the shoreline,
what is the angular velocity of the light at the time when beam is 1
mile from perpendicular?

what are ur choices?

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60

your mom

step-by-step explanation:

hello 0xxbadwolfxx0,

2.6 x 10^9 is 2,600,000,000.

1.3 x 10^2 is 130

multiplying 130 and 2,600,000,000 would simply give you 200,000,000,000.

therefore, the answer would be d. 2.0 × 10^11.

i hope i ! warm regards, mae.