PLEASE EXPLAIN HOW YOU GOT ANSWER. A school administrator tells everyone in the building that they will be having a fire drill randomly sometime during the school day which is from 8 a. m. to 3 p. m. If second period is from 9:00 a. m. to 10:00 a. m., what is the probability of the fire drill happening during second period?

Step-by-step explanation:

Given

Required

Determine the probability that the fire drill happens in the second period

First, we need to convert both time range to hours.

8 am to 3 pm is 7 hours.

So:

9 am to 10 am is 1 hour.

So:

The required probability can then be calculated using:

In this case, it is:

answer: i think it is (1,-2)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2