A real-valued function f is said to be periodic with period T ≠ 0 if f(x + T) = f(x) for all x in the domain of f. If T is the smallest positive value for which f(x + T) = f(x) holds, then T is called the fundamental period of f. Determine the fundamental period T of the given function. f(x) = cos(2πx)

f(x) = cos 2πx

Thus the fundamental period T = 1  

Step-by-step explanation:

From the information given:

The periodic function f(x + T) = f(x)   T ≠ 0  provided that  T is the smallest positive value  for which f(x + T) = f(x) holds, then T is called the fundamental period of f.

Now, for the given function f(x) = cos(2πx)

suppose T = 1/4 since T ≠ 0  

Then:

f(x+ 1/4) = cos(2π (x + 1/4) )

f(x+ 1/4) = cos (2πx + π/2)

f(x+ 1/4) = -sin 2πx        (Not satisfied)

suppose T = 1/2 since T ≠ 0  

Then:

f(x+ 1/2) = cos(2π (x + 1/2) )

f(x+ 1/2) = cos (2πx + π)

f(x+ 1/2) = -cos 2πx        (Not satisfied)

suppose T = 1 since T ≠ 0  

Then:

f(x+ 1) = cos(2π (x + 1) )

f(x+ 1) = cos (2πx + 2π)

f(x+ 1) = cos 2πx      

f(x+ 1) =  f(x)

f(x) = cos 2πx      

Therefore, the fundamental period T = 1  since  f(x) = cos 2πx  

noncoplanar points are points that do not lie on the same line.