Construction of segments angles and bisectors What are the steps for using a compass and straightedge to construct a line through point X that is parallel to line r?

1. Use the straightedge to draw a line s that passes through X and intersects line r. Label the point of intersection as point Y.

2. Place the point of the compass on point Y and draw an arc that intersects lines r and s. Label the intersections as points M and N.

3. Without changing the width of the compass opening, place the point of the compass on point X and draw an arc that intersects line s. Label the intersection as point P.

4. Place the point of the compass on point M and open it to width MN.

5. With the compass opening set to width MN, place the point of the compass on point P and draw an arc that intersects the arc that was drawn from point X. Label the intersection of the arcs as point Z.

6. Use the straightedge to draw XZ.

Step-by-step explanation:

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step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true