Jordan has 3 blue shirts, 4 red shirts and 6 orange shirts. She chooses a shirt for Monday and places it in her suitcase. Then, she chooses a shirt for Tuesday. What is the probability that she choose a red shirt for Monday and an orange shirt for Tuesday?

30% on Monday 46% on Tuesday

Step-by-step explanation:

Well you have 3 blue shirts 4 red shirts and 6 orange shirts so what you have to do is add all them together to make it a fraction which you would do 3+4+6 which is 13/13 so the probability of her wearing a red shirt on Monday would be 4/13 since there are 4 red shirts and 13 in total so we make 4/13 as a fraction which would give us 30% chance she would choose a red shirt on Monday and for Tuesday we do the same thing but instead we use orange shirts so which is 6/13 which would give her a percentage of 46% on Tuesday it's more closer to half than the red shirts because 6 pretty much half of 13 but since 13 is a odd number it isn't  half because half of 13 is 6.5

2? if not the correct answer you might need to provide more information

step-by-step explanation:

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.