Mathematics, 28.10.2020 02:00 bryanna0105

Due Today!! Line v passes through point (6, 6)
and is perpendicular to the graph 9
y − 1 = 4(x + 8) y = −4x + 15 16x + 4y = 9 y = −4x of y = _3_x − 11. Line w is parallel 4 to line v and passes through point (−6, 10). What is the equation in slope-intercept form of line w?

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Due Today!! Line v passes through point (6, 6)
and is perpendicular to the graph 9
y − 1...

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More questions: Mathematics Another questions

Due Today!! Line v passes through point (6, 6)and is perpendicular to the graph 9y − 1 = 4(x + 8) y = −4x + 15 16x + 4y = 9 y = −4x of y = _3_x − 11. Line w is parallel 4 to line v and passes through point (−6, 10). What is the equation in slope-intercept form of line w?

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Another question on Mathematics

Due Today!! Line v passes through point (6, 6)
and is perpendicular to the graph 9
y − 1 = 4(x + 8) y = −4x + 15 16x + 4y = 9 y = −4x of y = _3_x − 11. Line w is parallel 4 to line v and passes through point (−6, 10). What is the equation in slope-intercept form of line w?