When the light turns green, Mark accelerates straight down the road at 1.8 m/s2 for 8 seconds. What is his final velocity at the end of those 8 seconds?

Mark's final velocity at the end of the 8 seconds is 9.6 m/s

Step-by-step explanation:

The acceleration of mark after the light turns green, a = 1.8 m/s²

The time duration of the motion with the 1.8 m/s² acceleration,  t = 8 seconds

Mark's final velocity at the end of the 8 seconds, v is found using the equation of motion for velocity as follows;

v = u + a × t

Where;

u = The initial velocity = 0 m/s

a = The acceleration = 1.8 m/s²

t = The time in motion = 8 seconds

Substituting gives;

v = 0 + 1.2 × 8 = 9.6

Mark's final velocity at the end of the 8 seconds, v = 9.6 m/s.

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

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