A component is assembled in a four-step process. The probability of making a defect in step 1 is .10; in step 2, .20; in step 3, .08; and in step 4, .05. What is the probability that the component will be defective

0.371

Step-by-step explanation:

Given that:

Assembly requires a 4 step process:

Probability distribution of defect :

P(step 1) = 0.1

P(step 2) = 0.2

P(step 3) = 0.08

P(step 4) = 0.05

Firstly, we find the probability that there is no defect in each of the assembly process :

Probability of no defect: = (1 - p(defect))

P(step 1) = 1 - 0.1 = 0.9

P(step 2) = 1 - 0.2 = 0.8

P(step 3) = 1 - 0.08 = 0.92

P(step 4) = 1 - 0.05 = 0.95

Hence,

P(no_defect) = 0.9 * 0.8 * 0.92 * 0.95 = 0.62928

Probability of having a defective component ;

P(defect) = P(no_defect)' = 1 - p(no-defect)

1 - 0.62928 = 0.37072

0.37072

= 0.371

step-by-step explanation:

20% of 120 is 24. if you subtract 24 from 120 you get 96

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.