The coffee and soup machine at the local subway station is supposed to fill cups with 6 ounces of soup. Ten cups of soup are bought with results of a mean of 5.93 ounces and a standard deviation of .13 ounces. Construct a 99 percent confidence interval for the true machine-fill amount.

99% Confidence Interval = (5.824,6.036)

Step-by-step explanation:

The coffee and soup machine at the local subway station is supposed to fill cups with 6 ounces of soup. Ten cups of soup are bought with results of a mean of 5.93 ounces and a standard deviation of .13 ounces. Construct a 99 percent confidence interval for the true machine-fill amount.

The formula for confidence interval

= Mean ± z × σ/√n

Mean of 5.93 ounces

Standard deviation of .13 ounces.

n = 10 cups

z= z score of 99% confidence interval = 2.58

Confidence Interval =

5.93 ± 2.58 × 0.13/√10

5.93 ± 2.58 × 0.0411096096

Confidence Interval = 5.93 ± 0.106

= 5.93 - 0.106

= 5.824

= 5.93 + 0.106

= 6.036

Hence, Confidence Interval = (5.824,6.036)

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step-by-step explanation:

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