The sum of two consecutive odd integers is 20 less than four times the smaller of two integers. which of the following equations could be used to find the smaller integer, n? (1) (n+1)+(n+3)=20-4n
(2) n+(n+2)=4n-20
(3) (n+3)+n=20-4n
(4) n+(n+2)=4(n-20)

the answer would be c:   ax + b = ax + c

step-by-step explanation:

$5.41

step-by-step explanation:

$20 - $14.51 = $5.49.

v=1788.75

step-by-step explanation:

i belive that is the answer

given the equation is 8+9z=-6, the first step would be to subtract the 8 from both sides:

8+9z-8=-6-8

since 8 minus 8 = 0, this would cancel out the 8. and since -6 minus 8 equals -14, the equation would look like this

9z = -14