You are working as a cashier. You start with $500 in your cash register and the money in the cash register increases by $1000 each hour. Given: f(x) = 1000x +500 Part A Solve for x when f(x) = 2000 Part B What does the solution mean in context?

The answer is below

Step-by-step explanation:

A linear function is given as y = mx + b, where y is a dependent variable, x is an independent variable, m is the rate of change and b is the initial value of y (that is when x = 0).

Let x represent the number of hours and f(x) the amount of money in the cash register. Given that the cash register increases by $1000 each hour and the initial value of money in the cash register is $500. hence:

f(x) = 1000x + 500

a) At f(x) = 2000

2000 = 1000x + 500

1000x = 1500

x = 1500/1000

x = 1.5 hours

b) This means that after 1.5 hours, the amount of money in the cash register is $2000

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