Your above-ground pool has sprung a leak, and you do not have a way to fix it. At 12 noon, the water in the pool is 5 feet deep (in other words, the water level is 5 feet above the ground). You are not sure how quickly the pool level is falling, so you check again after 40 minutes and see that the height of the water level is now 4 feet. You notice that there is a relationship between the time that has passed to the height of the water level in the pool. If you assume the height of the water level is decreasing at a constant rate, what will be the height of the water level at 1 p. m.?
ft.
Write a linear function, h, that relates the time past noon, t, in minutes, and the height of the water level in the pool,
h(t)
h(t), in feet. (write the slope as a fraction)
h(t)=
h(t)=
t +
Explain the meaning of the rate of change of function. The water goes down
foot every minutes.
Evaluate
h(75)=
h(75)=
which means that when 75 minutes have passed, the height of the water level is feet.
At what time, t, will
h(t)=0.5?
h(t)=0.5?
Which means that after minutes the height of the water level will be 0.5 feet.
When you check the pool at 3 p. m., the height of the water level is approximately 1 foot, 4 inches. What conclusions can you draw?
The water level was higher/lower
than expected. It did/did not empty at a constant rate.