On a trip, the fare was 50¢ for each adult and 25¢ for each child. if 30 passengers paid $12.25, how many adults and children went?
which of the following equations could not be used to solve the problem?

50x + 25(30 - x) = 1225
50(30 - x) + 25x = 1225
25x + 50x = 30(1225)

25x + 50x = 30(1225)

Step-by-step explanation:

Given,

Total passenger = 30

There can be only two cases,

Case 1 : Let x be the number of adults,

So, the number of children = 30 - x,

Since, the total fare is $12.25 or 1225¢ ( 1 dollar = 100 cents ) in which 50¢ is for each adult and 25¢ is for each child,

⇒ 50x + 25(30 - x) = 1225,

Case 2 : let x be the number of children,

So, the number of adult = 30 - x,

The equation would be,

⇒ 50(30 - x) + 25x = 1225

Hence, the equations that could not be used to solve the given problem is,

25x + 50x = 30(1225)

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3