Peter is saving to buy a new camera. The camera cost $50. Peter has already saved $23.25. His plan is to save $4.50 every week to save at least enough for the camera. Part A: Write an inequality to model this situation.

Part B: How many weeks will it take Peter to save at least enough to buy the camera?

m ≥ 6

Here, m is the number of weeks Peter need to save money.

Step-by-step explanation:

The cost of the camera = $50

The amount of money already saved  = $23.25

The money saved  in 1 week = $4.50

Now, The TOTAL money LEFT to be saved = Total camera cost  - Money already saved

=  $50 - $23.25 = $26.75

So, there is $26.75 yet to be saved.

Let us assume it takes m weeks to save $26.75.

So, money saved in m weeks  = m x ( Money saved in 1 week)

or, $26.75. = m x ( $4.50)

or, m  =  $26.75 /$4.50 =  5.94

or, m = 5.94 ≈ 6 weeks

So, the money saved in at least 6 weeks  =  $26.75.

Hence, it would take AT LEAST 6 weeks to save up enough amount to buy the camera which costs $50.

⇒ m ≥ 6

Step-by-step explanation:

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x