A truck can be rented from Company A for $60 a day plus $0.20 per mile. Company B charges $20 a day plus $0.60 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.

So this isn't a

This is to help you understand how to do it in the future.

So we are going to let HOW MANY MILES GO BY be represented as (m)

Company A

60 + (m + .20) = final cost

Company B

20 + (m + .60) = final cost

Now you have to plug in numbers till you get your total miles left.

Have a good Day!!

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b