what is the equation in slope-intercept form of the line that crosses the x-axis at 36 and is perpendicular to the line that is represented by y=-4/9x+5?

The equation in slope-intercept form of the line that crossed the x-axis at 36 and is perpendicular to the line represented by y = -4/9x + 5 is

y=9/4x+36

Solution:

We have to find the line equation which is perpendicular to the given line in slope intercept form.

Now, let us find the slope of the given line.

Given line is in slope intercept form,  

y = mx + c where m is slope and c is the intercept.

So, by comparison, slope of given line is

Now, we know that product of slopes of perpendicular lines = -1

And we are also given that, perpendicular line passes x aixs at 36. Which means that intercept of x – axis is 36.

Thus the equation in slope intercept form is found

y + 11 = (1/4)(x + 16)

step-by-step explanation:

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step-by-step explanation: