The sum of the digits of a two digit number is 13. If 27 is added to the number, the place of the digits are reversed. Then the required number is??

The number is = 10x+y

if reverse the digits, the number is: 10y+x

The sum of its digits is =  x+y=5

I suggest this system of equations:

(10y+x)-(10x+y)=27    ⇒9y-9x=27

x+y=5

We can solve this system of equations by the equalization method

x=5-y

9y-9(5-y)=27

9y-45+9y=27

18y=27+45

18y=72

y=72/18

y=4

x=5-y

x=5-4=1

The number is: 10x+y=10(1)+4=14

the number is 14

it could be 1,3 and more others to create a cylinder.

step-by-step explanation: