Write a linear function rule for the data in the table x: 0, 1, 2, 3, 4

y: -5, -3, -1, 1, 3

A- f(x)=2x+3

B- f(x)=-2x+3

C- f(x)= 2x-6

D- f(x)= -2x-6

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70

fwms@lil_ben06

step-by-step explanation: