Select the combination of carbohydrates and fat meet the constraint of 120 calories.
A particular diet sets a constraint of 120 calories per snack. One gram of
carbohydrates provides 4 calories. One gram of fat provides 9 calories,
The equation that models the amount of calories in the snack is
4c + 9f = 120 where c is the number of grams of carbohydrates and
f is the number of grams of fat.
4 grams of carbohydrates and 12 grams of fat
4 grams of carbohydrates and 21 grams of fat
3 grams of carbohydrates and 12 grams of fat
3 grams of carbohydrates and 13 grams of fat

Given:

The equation that models the amount of calories in the snack is

where c is the number of grams of carbohydrates and  f is the number of grams of fat.

To find:

The combination of carbohydrates and fat meet the constraint  of 120 calories.

Solution:

In option A, 4 grams of carbohydrates and 12 grams of fat.

Put c=4 and f=12 in the given equation.

In option B, 4 grams of carbohydrates and 21 grams of fat.

Put c=4 and f=21 in the given equation.

In option C, 3 grams of carbohydrates and 12 grams of fat.

Put c=3 and f=12 in the given equation.

In option D, 3 grams of carbohydrates and 13 grams of fat.

Put c=3 and f=13 in the given equation.

Only the combination of 3 grams of carbohydrates and 12 grams of fat meet the constraint  of 120 calories.

Therefore, the correct option is C.

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

step-by-step explanation: