When playing many games, players must roll a pair of dice and find the sum of the two numbers rolled. With two dice, there are 11 possible sums ranging from 2 through 12. What is the probability that a player will roll a sum of 11 on his first roll of two dice? Express your answer as a common fraction.

Step-by-step explanation:

Given

Required

Probability of getting sum of 11

First, we need to list out the sample space;

Represent the first dice with S1 and the second with S2

Represent the Sum of the outcome with S

So, the new sample space is the sum of outcome of S1 and S2

So, S is as follows:

Represent the number of sample space with n(S)

To determine the probability of outcome of 11, we need to list out the number of outcomes of 11.

Represent this with n(11)

From the sample space above,

The required probability is then calculated as thus:

Simplify to the least term

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.