(x2 + 2xy + y2)(x+1) A) X3 + 2x2y + x2 + y2 +xy2
B) X2 + 2xy + y2
C) x3 + x2 +2x2y +xy2 + y2 + 2xy
D) x2 + y2 + 2xy + x + 1

Please show me how you solved it, I'm struggling with these and need an example to follow off of to complete the assignment so I can understand it better. Thank you!

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)