What is the answer to this problem? 7≥5y+16–8y≥-2

1 Simplify 5y+16-8y-25y+16−8y−2 to -3y+14−3y+14.

7\ge -3y+147≥−3y+14

2 Subtract 1414 from both sides.

7-14\ge -3y7−14≥−3y

3 Simplify 7-147−14 to -7−7.

-7\ge -3y−7≥−3y

4 Divide both sides by -3−3.

\frac{-7}{-3}\le y

−3

−7

≤y

5 Two negatives make a positive.

\frac{7}{3}\le y

3

7

≤y

6 Switch sides.

y\ge \frac{7}{3}y≥

3

7