Write a polynomial function that has a leading coefficient of 1, and the given zeros at 3, 5, and -i.

9514 1400 393

  p(x) = x^4 -8x^3 +16x^2 -8x +15

Step-by-step explanation:

Assuming you want real coefficients, the imaginary root means its conjugate is also a root. In factored form, the polynomial is ...

  p(x) = (x -3)(x -5)(x -i)(x +i) = (x^2 -8x +15)(x^2 +1)

  p(x) = x^4 -8x^3 +16x^2 -8x +15

where did you get them? if you picked from the grass, is is probably poisonous.

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!