Write an equation for the line parallel to y=2x - 4 that passes through (1 , 2)

y=2x

Step-by-step explanation:

parallel lines have the same gradient hence to find the equation u use the point given and an unknown point and the gradient

(1,2)&(x,y)=2

y-2/x-1=2

y-2=2x-2

y=2x

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step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15