Give the equation of the line going through the point (0, -3) and perpendicular to 4x - 8y = 16. Please answer quickly. It's due tomorrow

y=-1/4x+3

Step-by-step explanation:

put it into y-y1=m(x-x1) form, which gives you y+3=-1/4x(x+0)

(side note: we change the y- to a y+ becuase the y in the point in negative. another side note, the slope is -1/4x because perpendicular slopes are opposite, in this case 4x (or 4/1x) is the opposite of -1/4 x)

then remove the parenthesis. y+3=-1/4x

then isolate y and balance the equation.

y+3-3=-1/4x-3

this gives you the answer of y=-1/4x-3.

y=-2x-3

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=x2−2.  

The slope of the perpendicular line is negative inverse: m=−2.

So, the equation of the perpendicular line is y=−2x+a.

To find a, we use the fact that the line should pass through the given point: −3=(−2)⋅(0)+a.

Thus, a=−3.

Therefore, the equation of the line is y=−2x−3.

y=−2x−3.

figure c

step-by-step explanation:

hope this .

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.