The proportion of brown M&M’s in a milk chocolate packet is approximately 14% (Madison, 2013). Suppose a package of M&M’s typically contains 52 M&M’s. a.) State the random variable. b.) Find the mean. c.) Find the variance. d.) Find the standard deviation.

a) Let x be a random variable that represents the number of brown M&M’s in a milk chocolate packet.

b) Mean =7.28

c) Variance = 6.2608

d) Standard deviation = 2.5022

Step-by-step explanation:

Given : The proportion of brown M&M’s in a milk chocolate packet is approximately : p=14% =0.14

We have outcomes for every randomly selection : 1) its in a milk chocolate packet 2) its not.

a) Let x be a random variable that represents the number of brown M&M’s in a milk chocolate packet.

So x follows binomial distribution.

b) Sample size : n=52  (given)

Mean

c) Variance =

d) Standard deviation =

im here

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)