What are the first five terms of the sequence defined by the given function? f(1)=-6
f(n)=f(n-1)+2, for n=2,3,4

A. -6, -8, -10, -12, -14
B. 2, 8, 14, 20, 26
C. 2, -4, -10, -16, -22
D. -6, -4, -2, 0, 2

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)