Suppose a 5-mintue overseas call costs 6.45 and a 10-minute calls costs 11.40. The cost of a call and the length of a call care related. Write an equation to show the cost of a call for any duration. Approximately how long can you talk on the phone if you have $51 to spend?

The Equation for this is given as

C = $0.99x + $1.50

Where x = number of minutes

C = Cost of the call

If you have $51 to spend , the duration of the call is approximately 50 minutes

Step-by-step explanation:

Step 1

The difference in the cost of the calls is calculated as:

$11.40 - $6.45

= $4.95

The cost for a 5 minute call is calculated as:

$4.95 ÷ 5 = $0.99

Extra charges for the 5 minutes call =

$6.45 - $4.95 = $1.50

The Equation for this is given as

C = $0.99x + $1.50

Where x = number of minutes

C = Cost of the call

If you have $51 to spend, the number of minutes you would get is :

$51 = $0.99x + $1.50

$51 - $1.50 = 0.99x

$49.50 = 0.99x

x= $49.50/0.99

x = 50 minutes

Therefore, If you have $51 to spend , the duration of the call is approximately 50 minutes.

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.