OK FRFR THO HOW I GO TO 328 POINT TO 1328 LOL IMA DO A GIVE AWAY

Multiply −2x(6x^4−7x^2+x−5) express the answer in standard form. enter your answer in the box.

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Which shows the pre image of triangle xyz