![f(x)=3x^2-12x+1\\\\f(x)=3(x^2-4x)+1\\\\f(x)=3(x^2-2\cdot x\cdot2+2^2-2^2)+1\\\\f(x)=3(\underline{x^2-4x+4}-4)+1\\\\f(x)=3[(x-2)^2-4]+1\\\\f(x)=3(x-2)^2-12+1\\\\f(x)=3(x-2)^2-11](/tpl/images/0857/0943/416b3.png)
F(x) = 3x2 – 12x +1
find the vertex....
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