Solve for x and y.

(please help asap)

x = 4

y = 1

Step-by-step explanation:

At first, let us find the third angle in the triangle which has a right angle and an acute angle of measure 52°

∵ The sum of the interior angles of a triangle is 180°

∴ 52° + 90° + (6x + 14y)° = 180°

→ Add the like terms

∴ 142° + (6x + 14y) = 180°

→ Subtract 142° from both sides

∴ (6x + 14y)° = 38° ⇒ (1)

→ By using the two triangles

∵ The two triangles are congruent

∴ (15x - 8y) = 52° ⇒ (2)

Now we have a system of equations to solve it

→ Multiply equation (1) by 5 and equation (2) by -2 to make the

   coefficients of x equal in values and different in signs

∵ 5(6x + 14y) = 5(38)

∴ 30x + 70y = 190 ⇒ (3)

∵ -2(15x - 8y) = -2(52)

∴ -30x + 16y = -104 ⇒ (4)

→ Add equations (3) and (4) to eliminate x

∵ 86y = 86

→ Divide both sides by 86 to find y

∴ y = 1

→ Substitute the value of y in equation (1) to find x

∵ 6x + 14(1) = 38

∴ 6x + 14 = 38

→ Subtract 14 from both sides

∴ 6x = 24

→ Divide both sides by 6

∴ x = 4