If S=4πr^2 , find the value of S when r = 10 whole1/2. *

Step-by-step explanation:R=14

HERE

r = 10 whloe 1/2

= 21/2

We have ,

s = 4× pie × r ^2

= 4× (22/7) × (21/2)^2

= 4 × (22/7) × (441/2)

= 4 × 11 ×63

= 2772.

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0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

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