Arrange the equations in order from least to greatest based on their solution plz

The equations arranged in order from least to greatest based on their solution is  Equation B < Equation C < Equation A

For Equation A

First, clear the fraction by multiplying through by 4

Now, clear the brackets

Collect like terms

Then,

Divide both sides by 26

∴ For Equation A,

For Equation B

First, clear the bracket

Now, collect like terms

Divide both sides by 10.57

∴ For Equation B,

For Equation C

First, clear the brackets

Now, collect like terms

Then,

Divide both sides by 49

∴ For Equation C,

For Equation A,

For Equation B,

For Equation C,

Arranging the solutions from the least to greatest, we get

1.48 < 2.27 < 3.69

∴ Equation B < Equation C < Equation A

Hence, the equations arranged in order from least to greatest based on their solution is  Equation B < Equation C < Equation A

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x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.