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please solve this system of equations:
-4x-5y=-19
-9x-7y=-13

hi there!! :)

the answer should be (-4,5) or x = -4, y = 5

Step-by-step explanation:

1. You'd want to solve this system using elimination because both equations are written in standard form so it would be easiest. To do this, you need to choose which variable you want to eliminate. I'm going to eliminate the Y viariables.

so, you'd need to first find the LCM of the two variables. The LCM for 5 and 7 would be 35. So, you would multiply the entire top equation by -7 and the entire bottom equation by 5 so that your y viariables will end up being -45y and 45y, therefore cancelling each other out.

2. Completing step 1 will leave you with the following system:

28x = 133

-45x = -65

So, next we need to combine these two equations through adding like variables. this will mean we need to add 28x + -45x and 133 + -65

This will leave us with -17x = 68

3. Now, we need to isolate the x variable to solve for x. This is done through dividing both sides of the equation by -17. This will leave us with x = -4.

4. Now, we need to find y. To do this, you would pick one of the equations and solve it using the x value we just found. So, using this on the top equation, we would need to solve -4(-4) - 5y = -19.

First, multiply what's in the parentheses. this leaves us with 16 - 5y = -19. Now, we need to begin isolating the y value. This means subtracting the 16 from both sides of the equation, leaving us with -5y = -35. Now, to finish off, we would complete isolating the y variable through dividing both sides by -5. This will leave us with y = 7.

5. This all means that the answer should be (-4,5) or x = -4, y = 5

Hope this helps!!

answer: the value of x is 7cm

step-by-step explanation:

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.